(4)e1=FLD0+e2(0.784854−0.008565 e2)
and in the right hand side of the FLD where e2<0, the values of e1 and e2 are related to each other as in below equation
(5)e1=FLD0+e2(0.027254 e2−1.1965)
The FLD0 is the engineering failure strain in plain strain condition where e2=0. The statistical value of FLD0 can be calculated using below equation
(6)FLD0=n0.2116(23.25+356.1C1)
The value of C1 for thicknesses (t0) less than 0.29972 mm is equal to t0/25.4. However for larger thickness values, C1 is considered to be equal to 0.0118.
Calculating the values of e1 and e2, the true major and minor strains of the FLD (ɛ1 and ɛ2) are calculated using below equation
(7)ɛ1=ln(1+e1100)ɛ2=ln(1+e2100)
Using the statistical FLD as the ductile fracture criterion, for each element of the blank in FE model, the minor strain of this element is used and the major failure strain is calculated using the present method. If the true strain value of this element is less than the calculated failure strain, the element is considered to be formed without any fracture and vise versa.
M-K Method Using Hill's Nonquadratic Yielding Criterion.
Dariani and Azodi, based on the M-K method, calculated the FLD using the Hill's nonquadratic yielding criterion [35]. According to the Hill's nonquadratic yielding criterion, in the plane stress state and for in-plane isotropic materials, the sheet metal yields when the following Eq. (8) is satisfied
(8)|σ1+σ2|M+(2r+1)|σ1−σ2|M=2(r+1)σMe
where M is the Hill index, r is the normal anisotropy ratio, σ1 and σ2 are the principal stresses. They suggested that the Hill index (M) of 2.5–4 has good agreement with the experimental FLD of different materials.